A function abc is defined as
void abc (int   x =0, int y, int z=0)
{
       cout  <<  x  << y   << z ;
}
which of the following function calls is/are illegal? (Assume h , g  are declared as integers)

int    a=1,   b=2;

a=chg(b);

cout <<a<<b;

If the function chg is coded as

Int chg (int   x)

{

     x=10;

     retrun(11);

}

Then

int    a=1,   b=2;

a=chg(b);

cout <<a<<b;

If the function chg is coded as

int chg (int    &x )

{

 x  =10;

return(11);

}

Then

int    a=1,   b=2;

a=chg(b);

cout <<a<<b;

If the function chg is coded as

int  chg(const int &x)

{

    x=10;

    return (11)

}

Then

Consider the follwing program segment:

const char *p1=”To make the bitter butter better“;  // stm1

char *const p2= “ Recommend this book 2 others“;  // stm2

p1= “add some better butter not bitter“;   //stm3

p2="so that they 2 will get benefited.";  //stm4

*(p1+3)=’A’   ;  //stm5

*(p2+3)=’A’;    // stm6

Which of the statement results in error?

The following program

void abc (int    &p)

{cout    << p;  }

void main (void )

{

float m =   1.23;

abc (m);

cout    << m ;

}

choose the best answer: 

A function that does the same operation on different data types is to be implemented using

What is the output of the following C++program?

void abc( int x=0, int y=0)

{

  cout <<“Hi There“;

}

void abc(int x)

{

  cout <<”How R U doing today?":

}

void main (void)

{

  int m=5;

abc(m);

}

Consider the declarations

char  a;

const char aa=‘h’;

char *na;

const char *naa;

Which of the following statements is/are illegal?

Statement I:   aa = a;

Statement II:  na=  &a;

Statement III:  na=&aa;

#include ‘’iostream.h’’

int a(int m)

{ return ++m; }

int   b(int &m)

{ return   ++m; }

int c(char &m)

{ return ++m; }

void main(  )

{

  int   p=0, q=0 , r=0;

  p+=a (b(p));

  q+ =b(a (q));

  r+=a (c(r));

  cout <<p<<q<<r;

}

The above program prints: